Creativo - the topper's choice

www.creativo.co.in ( Lot of general aptitude questions available here )

Friday, April 28, 2006

Preparation

Preparation:

For C,C++--> Test ur C,C++ skills by Yashvanth kanithakar
For Java--> any good book.
Pattern:
48Q totally
12Q in General computer test?(Concentrate more on ceo's and founders of HP,Microsoft,intel,sap etc..)It even includes Q in OS,N/wing
12Q on C,
12Q on C++
12Q n java
All section r compulsory..(Even for Non java guys)

In the interview( ie ont he 2nd ropund..they will ask Q mostly in C,C++,Java.The employee who r asking the Q r very jovia
l.So develop ur confidence level.They mostly ask abt ur latest projects,
If u clear this level..next will be HR round.
If u clear the second round mostly..u r selected(90%).
HR is just for a formality..
The interview pattern will be as:
1. Tell abt your self.
2. They will ask for the subjects in which we are strong
( Here they will consider the ranking that we written during written
examination & marks we got in written exam)
3. Mostly the interview time will be 45 minutes around (for only
people there is about 1.5 hr)
4. HR questions may include here
5. Good thing is They r friendly and cooperative so confidence place
role.
If u don't know the answer better not to answer than to tell some bad
stuff.
For me 2 people interviewd. As I told them that I am strong in C
they told me to write some programs like double linked list, singly
linked list(adding node at last), macros, const *,char *,pointer
arrays.
The main question that they asked was how can u compile or
execute 'c' program without editor. (Using TCC utility)
coming 2 cpp only 1 question i.e what is polymorphism.
Java they asked me about protocol used in JSP, which layer does it
belongs to, main differences between _Javascript ,java and JSP.
During personal introduction try to excell your capabilities by
giving examples like as fast learner, hard worker like..!
If u have any achievements & awards try 2 put them all during
personal INtroduction.
The interviewers are very co-operative and highly friendly (so
confidence plays vital role)
There are four sections in the test
1.general ability(12q)
2.computer science(12q)
3.c/c++(12q)
4.java.(12q)
All the questions are mandatory. No negative marking
the questions are
section 1
1.Intel's first processor is
1)------2)4004 3) 80804)8086

2) Founder of Microsoft corporation
1) Bill Gates 2) Billgates and --------
3)Bill gates and Paul Allen4) Billgates and -------

3)Oddman out
1)Internet Explorer 2) Alt Vista3) Netscape Navigator 4)Opera

4)Which of the following is not a database
1)PLSQL2)MSSQL 3)MySQL4)Informix

5)Laura C--- (I don't remember exact spelling ) is CEO of
1)Oracle 2)DELL 3) Hp4)Intel
Ans) She is CEO of HP

6)'SUN' Microsystems SUN stands for
1)Simple Unified Network2)Solaris Unified Network3)-------------
4) None of the above.

section 2

1) IRC stands for ans) Internet Relay chat

2)ICQ stands for ans)--------------------

3)The protocol used to translate Internet address to Network addressis
1)IP2)TCP3)ARP4)RARP

4)In some OS the option that the system provides to communicate with
other process is
1)IPC(Inter Process Communication)2)----3)-----4)-----

5)VPN stands for ans) Virtual private network.

6)The time taken to transfer data from one place to other place or
process within specified time is
1)Throughput2)Latency time 3)Response time 4)----------

7)The time complexity for which of the following is O(n log n)
1) Radix sort 2)Quick sort3)Shell sort 4) Bubblesort.

8)Which of the following is used pass the packets between networks
1)--------2)Bridges3)Router4)Gateways

section 3


1)Which of the following can be used to print % to the screen
1) printf("\%");2)printf("\\%"); 3)----- 4)------

2)how many times the loop is executed
main()
{
int i=3;
while(i>=0)
printf("%d",i--);
return(0);
}
1) 3 2)Infinite 3)0 4)2
3) what is the output
int 1=10;
printf("%d %d %d ",i,++i,i++);


1) 10 11 11 2)11 11 10 3) 10 11 10 4) None of the above
4)
x=2;
y=5;
z=x+++y;
printf("%d %d %d",x,y,z);
1)----------- 2)------- 3)--------- 4)---------

5)In c++,
1)------------------
2)------------------
3)you cannot Overload new operator for a class
4)----------------------

6) Void xyz(char a[10])
{
int i;
i=sizeof(a);
printf("%d",i);
}
1)10 2)can't say 3) 2 4)same as size of pointer.

7) Local Variables is stored in which part of the memory
1) register or heap 2)heap 3)register or stack 4)-----
8) which of the following can be shared by progams
1)Text Code
2)Data segment
3)heap memory
4)--------
section 4
Sorry I don't remember the Java Questions


Iam giving the quesns on 3 sections.c/c++ was very
easy
For any further informn mail me.

4 sections
48 quesns
no negative marking
all objective quesns.

IT INformation

1. Who is associated with C language?
2. CEO of MIcrosoft
3.Company producing Routers,Bridges
4.From 70s 80s Company producing
mouse,GUIs............a)Dell b)IBM c) Xerox d) HP
5.Inventor of Pascal
6.Abt SUN micro systems
7.first digital comp machine a)von neumann b) Dijkstra
8.Which of these is not search engine a)hotbot
b)parametric c)Altavista d) google
9.In 2002 IBM acquired which company a) Rational b)
oracle c) netscape
10.founder of apple computer(2 persons)

Computer Concepts

1.Complexity nlogn a.quick sort b. bubble sort c.
shell sort
2.Abt Protocols
3.Abt SSL
4.Abt MBR
5.Cross compiler
6.synonymus to main memory
7.Semaphores
8.Database quesns Stored procedures
Trigger strategy
9.Bandwidth measured in ?
10.Term assoc with Context Transaction

Java

1.extending the class means
2.how many values does char of java has
3.Java pgm can be executed on any m/c how?
4.utility used for dynamically changing the tables
a.vector b. hash table c. enumeration
d. structures
5.synchronise means
6.if X & Y r objects X = Y means
7.which action Java platform restricts on applets
a. Image viewing
b. Accept user i/p
c. write to system files
d. initialise date in browser
8.quesns on JDBC
9.Two quesns on simple java pgms.
10. Java was initially code named as:
a)Oak b)green c)miller
11.) what is not true about the following statements
about java.
a) it is compiled using javac compiler
b) the compiled files have .class extension.
c) such files cannot be transfered from one comp to
another.
d) they use the java interpreter
Hi friends,
.There were 48 questions.There were 3 series of quesn
papers.
So prepare in general dont rely on the quesns that iam
going to send.
12 questions in each section
1> General IT information(easy)
2> C/C++ (very easy)
3> Computer Concepts(Database,Unix,....)
4> Java/JdBC (little tough)


The test comprises of 4 sections:
Section A. ------50qns(general appitude,english etc):
Section B. ------ 10 Questions on Computer concepts.
Section C. ------ 30 Questions on C
Duration 90min, no negative marking. one mark per question .
Once this is cleared then u must take a c programming test duration 40min.
5 programs,each got differnet papers.one i got was
1.WAP find and replace a character in a string.
2.WA function to perform the substraction of two .
Eg:char N1="123",N2="478",N3=-355(N1-N2).
3.WAP dynamically intialize a 2 dimentional array Eg:5x20,accept strings and check for vowels and display the no.finally free the space allocated .
4.WAP read a line from file from location N1 to N2 using command line agruments
Eg:exe 10 20 a.c freshersworld.com
5.WAP find the largest of 4 no using macros.


Some questions that i remember are...................
1>General section : computer science general knowledge
2> Computer science general: simple questions
1) HP acquired this company in 2002. Which is the company
a)Compaq b)Dell c)option 3 d) Option4
Ans: a
2) what does 3G denote
a) 3rd generation mobile communication b) 3rd generation computer languages c) option 3 d) option4
Ans: a
3)an application program that is used by the users to get the inofrmation from the backend of some
application like databases:
a) application server b)proxy server c)database server d)option 4
Ans: database server freshersworld.com
4) which of the following is not true about the e-mail
a) it can be accessed by a client program using POP
b) it can be accessed by a client program using imap protocol
c) option 3
d) option 4
Ans: I don't remember the answer but first 2 are true.
5) Some quesion regarding the company and who developed it ( the thing to remember is that Apple produce Macintosh computers).
5) What is X.25?
a)option 1 b)option 2 c)option 3 d)option 4
Ans: find out??:-)
3> c/c++ section: questions on c/c++, programs o/p etc.
1) main( )
{
unsigned int i=3; freshersworld.com
while( i >=0)
printf( "%d", i--);
}
how many times will the printf stmt be executed?
a)0 b)3 c)4 d)infinite
Ans: I think the answer is infinite, b'cos 'i' is an unsigned integer and it will not decrement below '0' and hence end up in an infinite loop.(yes, i checked and it is getting stuck in an infinite loop)
2) main( )
{
int x,y, z;
x=2;
y=5;
z= x+++y;
printf("%d %d %d", x, y z);
}
a)3 5 7 b)option 2 c)option 3 d)option 4
Ans: a
3) # define swap(a,b) temp=a; a=b; b=temp;
main( )
{ freshersworld.com
int i, j, temp;
i=5;
j=10;
temp=0;
if( i > j)
swap( i, j );
printf( "%d %d %d", i, j, temp);
}
Ans: On compiling i got ans 10, 0, 0. I did not understand the concept. Please expalin this to me.
4>Java section: questions on java related stuff.
1) Java was initially code named as:
a)Oak b)green c)miller d)option4
Ans: Oak
2) what is not true about the following statements about java.
a) it is compiled using javac compiler
b) the compiled files have .class extension.
c) such files cannot be transfered from one comp to another.
d) they use the java interpreter freshersworld.com
Ans: c
3) Why is the synchronize used?
a) to initialize multiple objects b)to lock an object c)option3 d)option 4
Ans: b (probably)
.................
.

.From 70s 80s Company producing
mouse,GUIs............a)Dell b)IBM c) Xerox d) HP



3)an application program that is used by the users to get the inofrmation from the backend of some application like databases:
a) application server b)proxy server c)database server d)option 4
Ans: database server


8.Database quesns Stored procedures
Trigger strategy
9.Bandwidth measured in ?
10.Term assoc with Context Transaction



2)ICQ stands for ans)--------------------


class A
{
A(int x)
{
System.out.println(" x=" + x );
}
A(int x,int y)
{
System.out.println(" x=" + x + " y =" + y);
}
}
class HPTest4
{
public static void main(String args[])
{
A a=new A(1);
A b=new A(2,3);
A c=new A();
}
}


HP Q Paper Pattern:-
48Q 1 hr
12Q General Knowledge
12Q General CSE
12Q C and C++
12Q Java

The q's r as follows:-


1. Which of the foll is not a protocol.

HTTP PIM PSI

A> PSI (check)

2> Which of the foll does not help security.

Good Password
Update Antivirus
VLAN

A> VLAN

3> What was the prob with Intel Processor

Cache
FPU
NONE
A> FIND OUT AND LET ME KNOW

4> What does MIME stand for

A> Multipurpose Mail Exchange Protocol

5> What does XP stand for in WIN-Xp
A> Experience

6> Who is associated with C
A> Dennis Ritchie

7> Which of the foll is not a IM client

AOL
MSN
JABBER
XINGC
A> XINGC

8> What does ERP stand 4

A> Enterprise resource planning.

9> Who is associated with HOTMAIL

SABEER Bhatia and Jack Smith
SABEER Bhatia and Bill Gates

A>SABEER Bhatia and Jack Smith


10> What does UNIX stand 4???
Find out

11> Which of the foll is not a app server
BLUESTONE
WEBSPHERE
TOMCAT
JBOSS

A> BLUESTONE



GENERAL CSE Q's

12> What do u call software embbedded in ROM

BIOS
FIRMWARE
SHAREWARE
FREEWARE
A> BIOS (Verify and plz let me know)

13> What is semaphore used 4????


14> Integral Constraint helps in???

A> Solving Inconsitent Data prob.

15> PING uses

A> ICMP



16> IP ADDRESS occupies
4 bytes
8 bytes
16 bytes
6 bytes

A> I wrote 8. correct ans 4

17> Which DataStructure helps Searching
STACK
LINKED LIST
HASH
A> HASH

18> Q on Binary tree Depth?
2^n
2^n - 1
log n

19> Database shud hav
A> ACID properties.

20> VPN stands 4
A> virtual private n/w

21> what does fork() return 2 parent
child pid
0
A> 0


22> What do u call the relationship b/e a table and its columnz
A> Schema

12Q on c & c++

23> What is true about c++
A> IT can hav virtual constuctors

24> result of i=6; printf("%d",i++*i++)
36
54
cant say
A> Can't say (compiler dependent)


25> output of
char str[20] = "SANJAY"

printf("%d%d",sizeof(str),strlen(str))

ANS> 20,6

26> Which of the foll cannot b used accross files
extern
volatile
static
const
A> static. (i wrote volatile)

27> union u{ int i; char c;};
sizeof(u);

28> Idenitify err
5[[a]
5["abc"]
A> 5["abc"]

12Q on JAVA

29> Java alloctaes mem in
STACK
HEAP
A> HEAP
30> Can u call Garbage collector explicitly

A> S . Find out the syntax. It was asked

31> What does this mean X = Y

A> Object X refers to the contents of Y.

32> Q on Null pointer Exception

33> Synchronize is used 4???


Aptitude Questions

One guy has Rs. 100/- in hand. He has to buy 100 balls. One football costs Rs. 15/, One Cricket ball costs Re. 1/- and one table tennis ball costs Rs. 0.25 He spend the whole Rs. 100/- to buy the balls. How many of each balls he bought?

The distance between Station Atena and Station Barcena is 90 miles. A train starts from Atena towards Barcena. A bird starts at the same time from Barcena straight towards the moving train. On reaching the train, it instantaneously turns back and returns to Barcena. The bird makes these journeys from Barcena to the train and back to Barcena continuously till the train reaches Barcena. The bird finally returns to Barcena and rests. Calculate the total distance in miles the bird travels in the following two cases:
(a) The bird flies at 90 miles per hour and the speed of the train is 60 miles per hour.
(b) the bird flies at 60 miles per hour and the speed of the train is 90 miles per hour


A tennis championship is played on a knock-out basis, i.e., a player is out of the tournament when he loses a match.
(a) How many players participate in the tournament if 15 matches are totally played?
(b) How many matches are played in the tournament if 50 players totally participate?


When I add 4 times my age 4 years from now to 5 times my age 5 years from now, I get 10 times my current age. How old will I be 3 years from now?


A rich merchant had collected many gold coins. He did not want anybody to know about them. One day, his wife asked, "How many gold coins do we have?" After pausing a moment, he replied, "Well! If I divide the coins into two unequal numbers, then 37 times the difference between the two numbers equals the difference between the squares of the two numbers." The wife looked puzzled. Can you help the merchant's wife by finding out how many gold R


A set of football matches is to be organized in a "round-robin" fashion, i.e., every participating team plays a match against every other team once and only once. If 21 matches are totally played, how many teams participated?


Glenn and Jason each have a collection of cricket balls. Glenn said that if Jason would give him 2 of his balls they would have an equal number; but, if Glenn would give Jason 2 of his balls, Jason would have 2 times as many balls as Glenn. How many balls does Jason have?


Suppose 8 monkeys take 8 minutes to eat 8 bananas.
(a) How many minutes would it take 3 monkeys to eat 3 bananas?
(b) How many monkeys would it take to eat 48 bananas in 48 minutes


It was vacation time, and so I decided to visit my cousin's home. What a grand time we had! In the mornings, we both would go for a jog. The evenings were spent on the tennis court. Tiring as these activities were, we could manage only one per day, i.e., either we went for a jog or played tennis each day. There were days when we felt lazy and stayed home all day long. Now, there were 12 mornings when we did nothing, 18 evenings when we stayed at home, and a total of 14 days when we jogged or played tennis. For how many days did I stay at my cousin's place?


A 31" x 31" square metal plate needs to be fixed by a carpenter on to a wooden board. The carpenter uses nails all along the edges of the square such that there are 32 nails on each side of the square. Each nail is at the same distance from the neighboring nails. How many nails does the carpenter use?


Answer and Explanation.

F + C + T = 100-------------eq1
15F + C + 0.25T = 100-------------eq2
eq1=eq2 .solve to get F=3T/56 ;F=3,T=56,C=41


a) There is no need to consider their meeting pt at all.the train has been running for 90miles/(60miles/hr)=1.5hrs.bird flies till train reaches destination frm strting pt.so bird flies for1.5hrs at the vel given(90).so dist=1.5*90=135miles

b) time of train=1hr.so dist of bird=60*1=60miles



(a) u don't need to sum it up.since it's a knock out only 1 person emerges winner finally.so15+1=16is answer.becos after15 matches finally we shud've 15losers and 1winner.

(b) 49:its always one less than no of players as per the idea given above.so no need to check okay cos its always true.ans is 49.


Let x= current age
4(x+4)+5(x+5)=10x ;so x=R 41 years


37(x-y)=x^2-y^2. u no tht x^2-y^2=(x-y)(x+y).so (x-y) cancels on both sides to give x+y=37.so sum of unequal halves=37 which is the req answer.


R ans:7 teams okay.for a match u need 2 teams.suppose there r totally 'n 'teams.
Now uve to choose 2 teams out of 'n' teams.so answer =no of such choices=no. of possible combinations. So we've ans = nC2(ncombination2)=21;solve to get n=7.
Sol: n(n-1)/2=21. so n=7.if u don't understand c the graph below
each team plays no. of matches=no of teams ahead of it. One bar '|' represents one team.
| | | | | | | ------------7
6 5 4 3 2 1 0 -----------21
last team is written as 0 matches becos this team has already played with all other teams-hence sum of matches =6+5+4+3+2+1=21 which is correct only if no of teams =7


R 14
1. G+2=j-2
2. 2(G-2)=J+2.
solve these 2 to get
J=14


a). Sol:each mky takes 8 min to eat a banana

b).ans:8m=48 m=6


Use sets and venn diagram to solve such questions.a,b ,aub,anb etc.
12=tennis+leave
18=jog +leave
so jog-tennis=6
again jog+tennis=14.so solve and get jog=10,leave=8,tennis=4.so tot=22


Ans= 32*2 + 30*2=124







C++ Aptitude

C++ Questions

Note : All the programs are tested under Turbo C++ 3.0, 4.5 and Microsoft VC++ 6.0 compilers.

It is assumed that,

Ø Programs run under Windows environment,

Ø The underlying machine is an x86 based system,

Ø Program is compiled using Turbo C/C++ compiler.

The program output may depend on the information based on this assumptions (for example sizeof(int) == 2 may be assumed).

1) class Sample

{

public:

int *ptr;

Sample(int i)

{

ptr = new int(i);

}

~Sample()

{

delete ptr;

}

void PrintVal()

{

cout << "The value is " << *ptr;

}

};

void SomeFunc(Sample x)

{

cout << "Say i am in someFunc " <<>

}

int main()

{

Sample s1= 10;

SomeFunc(s1);

s1.PrintVal();

}

Answer:

Say i am in someFunc

Null pointer assignment(Run-time error)

Explanation:

As the object is passed by value to SomeFunc the destructor of the object is called when the control returns from the function. So when PrintVal is called it meets up with ptr that has been freed.The solution is to pass the Sample object by reference to SomeFunc:

void SomeFunc(Sample &x)

{

cout << "Say i am in someFunc " <<>

}

because when we pass objects by refernece that object is not destroyed. while returning from the function.

2) Which is the parameter that is added to every non-static member function when it is called?

Answer:

‘this’ pointer

3) class base

{

public:

int bval;

base(){ bval=0;}

};

class deri:public base

{

public:

int dval;

deri(){ dval=1;}

};

void SomeFunc(base *arr,int size)

{

for(int i=0; i

cout<bval;

cout<

}

int main()

{

base BaseArr[5];

SomeFunc(BaseArr,5);

deri DeriArr[5];

SomeFunc(DeriArr,5);

}

Answer:

00000

01010

Explanation:

The function SomeFunc expects two arguments.The first one is a pointer to an array of base class objects and the second one is the sizeof the array.The first call of someFunc calls it with an array of bae objects, so it works correctly and prints the bval of all the objects. When Somefunc is called the second time the argument passed is the pointeer to an array of derived class objects and not the array of base class objects. But that is what the function expects to be sent. So the derived class pointer is promoted to base class pointer and the address is sent to the function. SomeFunc() knows nothing about this and just treats the pointer as an array of base class objects. So when arr++ is met, the size of base class object is taken into consideration and is incremented by sizeof(int) bytes for bval (the deri class objects have bval and dval as members and so is of size >= sizeof(int)+sizeof(int) ).

4) class base

{

public:

void baseFun(){ cout<<"from base"<

};

class deri:public base

{

public:

void baseFun(){ cout<< "from derived"<

};

void SomeFunc(base *baseObj)

{

baseObj->baseFun();

}

int main()

{

base baseObject;

SomeFunc(&baseObject);

deri deriObject;

SomeFunc(&deriObject);

}

Answer:

from base

from base

Explanation:

As we have seen in the previous case, SomeFunc expects a pointer to a base class. Since a pointer to a derived class object is passed, it treats the argument only as a base class pointer and the corresponding base function is called.

5) class base

{

public:

virtual void baseFun(){ cout<<"from base"<

};

class deri:public base

{

public:

void baseFun(){ cout<< "from derived"<

};

void SomeFunc(base *baseObj)

{

baseObj->baseFun();

}

int main()

{

base baseObject;

SomeFunc(&baseObject);

deri deriObject;

SomeFunc(&deriObject);

}

Answer:

from base

from derived

Explanation:

Remember that baseFunc is a virtual function. That means that it supports run-time polymorphism. So the function corresponding to the derived class object is called.

void main()

{

int a, *pa, &ra;

pa = &a;

ra = a;

cout <<"a="<

}

/*

Answer :

Compiler Error: 'ra',reference must be initialized

Explanation :

Pointers are different from references. One of the main

differences is that the pointers can be both initialized and assigned,

whereas references can only be initialized. So this code issues an error.

*/

const int size = 5;

void print(int *ptr)

{

cout<

}

void print(int ptr[size])

{

cout<

}

void main()

{

int a[size] = {1,2,3,4,5};

int *b = new int(size);

print(a);

print(b);

}

/*

Answer:

Compiler Error : function 'void print(int *)' already has a body

Explanation:

Arrays cannot be passed to functions, only pointers (for arrays, base addresses)

can be passed. So the arguments int *ptr and int prt[size] have no difference

as function arguments. In other words, both the functoins have the same signature and

so cannot be overloaded.

*/

class some{

public:

~some()

{

cout<<"some's destructor"<

}

};

void main()

{

some s;

s.~some();

}

/*

Answer:

some's destructor

some's destructor

Explanation:

Destructors can be called explicitly. Here 's.~some()' explicitly calls the

destructor of 's'. When main() returns, destructor of s is called again,

hence the result.

*/

#include

class fig2d

{

int dim1;

int dim2;

public:

fig2d() { dim1=5; dim2=6;}

virtual void operator<<(ostream & rhs);

};

void fig2d::operator<<(ostream &rhs)

{

rhs <dim1<<" "<dim2<<" ";

}

/*class fig3d : public fig2d

{

int dim3;

public:

fig3d() { dim3=7;}

virtual void operator<<(ostream &rhs);

};

void fig3d::operator<<(ostream &rhs)

{

fig2d::operator <<(rhs);

rhs<dim3;

}

*/

void main()

{

fig2d obj1;

// fig3d obj2;

obj1 <<>

// obj2 <<>

}

/*

Answer :

5 6

Explanation:

In this program, the <<>

This enables the 'cout' to be present at the right-hand-side. Normally, 'cout'

is implemented as global function, but it doesn't mean that 'cout' is not possible

to be overloaded as member function.

Overloading <<>

it is overloaded is inherited, and this becomes available to be overrided. This is as opposed

to global friend functions, where friend's are not inherited.

*/

class opOverload{

public:

bool operator==(opOverload temp);

};

bool opOverload::operator==(opOverload temp){

if(*this == temp ){

cout<<"The both are same objects\n";

return true;

}

else{

cout<<"The both are different\n";

return false;

}

}

void main(){

opOverload a1, a2;

a1= =a2;

}

Answer :

Runtime Error: Stack Overflow

Explanation :

Just like normal functions, operator functions can be called recursively. This program just illustrates that point, by calling the operator == function recursively, leading to an infinite loop.

class complex{

double re;

double im;

public:

complex() : re(1),im(0.5) {}

bool operator==(complex &rhs);

operator int(){}

};

bool complex::operator == (complex &rhs){

if((this->re == rhs.re) && (this->im == rhs.im))

return true;

else

return false;

}

int main(){

complex c1;

cout<< c1;

}

Answer : Garbage value

Explanation:

The programmer wishes to print the complex object using output

re-direction operator,which he has not defined for his lass.But the compiler instead of giving an error sees the conversion function

and converts the user defined object to standard object and prints

some garbage value.

class complex{

double re;

double im;

public:

complex() : re(0),im(0) {}

complex(double n) { re=n,im=n;};

complex(int m,int n) { re=m,im=n;}

void print() { cout<

};

void main(){

complex c3;

double i=5;

c3 = i;

c3.print();

}

Answer:

5,5

Explanation:

Though no operator= function taking complex, double is defined, the double on the rhs is converted into a temporary object using the single argument constructor taking double and assigned to the lvalue.

void main()

{

int a, *pa, &ra;

pa = &a;

ra = a;

cout <<"a="<

}

Answer :

Compiler Error: 'ra',reference must be initialized

Explanation :

Pointers are different from references. One of the main

differences is that the pointers can be both initialized and assigned,

whereas references can only be initialized. So this code issues an error.

Try it Yourself

1) Determine the output of the 'C++' Codelet.

class base

{

public :

out()

{

cout<<"base ";

}

};

class deri{

public : out()

{

cout<<"deri ";

}

};

void main()

{ deri dp[3];

base *bp = (base*)dp;

for (int i=0; i<3;i++)

(bp++)->out();

}

2) Justify the use of virtual constructors and destructors in C++.

3) Each C++ object possesses the 4 member fns,(which can be declared by the programmer explicitly or by the implementation if they are not available). What are those 4 functions?

4) What is wrong with this class declaration?

class something

{

char *str;

public:

something(){

st = new char[10]; }

~something()

{

delete str;

}

};

5) Inheritance is also known as -------- relationship. Containership as ________ relationship.

6) When is it necessary to use member-wise initialization list (also known as header initialization list) in C++?

7) Which is the only operator in C++ which can be overloaded but NOT inherited.

8) Is there anything wrong with this C++ class declaration?

class temp

{

int value1;

mutable int value2;

public :

void fun(int val)

const{

((temp*) this)->value1 = 10;

value2 = 10;

}

};


1. What is a modifier?

Answer:

A modifier, also called a modifying function is a member function that changes the value of at least one data member. In other words, an operation that modifies the state of an object. Modifiers are also known as ‘mutators’.

2. What is an accessor?

Answer:

An accessor is a class operation that does not modify the state of an object. The accessor functions need to be declared as const operations

3. Differentiate between a template class and class template.

Answer:

Template class:

A generic definition or a parameterized class not instantiated until the client provides the needed information. It’s jargon for plain templates.

Class template:

A class template specifies how individual classes can be constructed much like the way a class specifies how individual objects can be constructed. It’s jargon for plain classes.

4. When does a name clash occur?

Answer:

A name clash occurs when a name is defined in more than one place. For example., two different class libraries could give two different classes the same name. If you try to use many class libraries at the same time, there is a fair chance that you will be unable to compile or link the program because of name clashes.

5. Define namespace.

Answer:

It is a feature in c++ to minimize name collisions in the global name space. This namespace keyword assigns a distinct name to a library that allows other libraries to use the same identifier names without creating any name collisions. Furthermore, the compiler uses the namespace signature for differentiating the definitions.

6. What is the use of ‘using’ declaration.

Answer:

A using declaration makes it possible to use a name from a namespace without the scope operator.

7. What is an Iterator class?

Answer:

A class that is used to traverse through the objects maintained by a container class. There are five categories of iterators:

Ø input iterators,

Ø output iterators,

Ø forward iterators,

Ø bidirectional iterators,

Ø random access.

An iterator is an entity that gives access to the contents of a container object without violating encapsulation constraints. Access to the contents is granted on a one-at-a-time basis in order. The order can be storage order (as in lists and queues) or some arbitrary order (as in array indices) or according to some ordering relation (as in an ordered binary tree). The iterator is a construct, which provides an interface that, when called, yields either the next element in the container, or some value denoting the fact that there are no more elements to examine. Iterators hide the details of access to and update of the elements of a container class.

The simplest and safest iterators are those that permit read-only access to the contents of a container class. The following code fragment shows how an iterator might appear in code:

cont_iter:=new cont_iterator();

x:=cont_iter.next();

while x/=none do

...

s(x);

...

x:=cont_iter.next();

end;

In this example, cont_iter is the name of the iterator. It is created on the first line by instantiation of cont_iterator class, an iterator class defined to iterate over some container class, cont. Succesive elements from the container are carried to x. The loop terminates when x is bound to some empty value. (Here, none)In the middle of the loop, there is s(x) an operation on x, the current element from the container. The next element of the container is obtained at the bottom of the loop.

9. List out some of the OODBMS available.

Answer:

Ø GEMSTONE/OPAL of Gemstone systems.

Ø ONTOS of Ontos.

Ø Objectivity of Objectivity inc.

Ø Versant of Versant object technology.

Ø Object store of Object Design.

Ø ARDENT of ARDENT software.

Ø POET of POET software.

10. List out some of the object-oriented methodologies.

Answer:

Ø Object Oriented Development (OOD) (Booch 1991,1994).

Ø Object Oriented Analysis and Design (OOA/D) (Coad and Yourdon 1991).

Ø Object Modelling Techniques (OMT) (Rumbaugh 1991).

Ø Object Oriented Software Engineering (Objectory) (Jacobson 1992).

Ø Object Oriented Analysis (OOA) (Shlaer and Mellor 1992).

Ø The Fusion Method (Coleman 1991).

11. What is an incomplete type?

Answer:

Incomplete types refers to pointers in which there is non availability of the implementation of the referenced location or it points to some location whose value is not available for modification.

Example:

int *i=0x400 // i points to address 400

*i=0; //set the value of memory location pointed by i.

Incomplete types are otherwise called uninitialized pointers.

12. What is a dangling pointer?

Answer:

A dangling pointer arises when you use the address of an object after its lifetime is over.

This may occur in situations like returning addresses of the automatic variables from a function or using the address of the memory block after it is freed.

13. Differentiate between the message and method.

Answer:

Message Method

Objects communicate by sending messages Provides response to a message.

to each other.

A message is sent to invoke a method. It is an implementation of an operation.

14. What is an adaptor class or Wrapper class?

Answer:

A class that has no functionality of its own. Its member functions hide the use of a third party software component or an object with the non-compatible interface or a non- object- oriented implementation.

15. What is a Null object?

Answer:

It is an object of some class whose purpose is to indicate that a real object of that class does not exist. One common use for a null object is a return value from a member function that is supposed to return an object with some specified properties but cannot find such an object.

16. What is class invariant?

Answer:

A class invariant is a condition that defines all valid states for an object. It is a logical condition to ensure the correct working of a class. Class invariants must hold when an object is created, and they must be preserved under all operations of the class. In particular all class invariants are both preconditions and post-conditions for all operations or member functions of the class.

17. What do you mean by Stack unwinding?

Answer:

It is a process during exception handling when the destructor is called for all local objects between the place where the exception was thrown and where it is caught.

18. Define precondition and post-condition to a member function.

Answer:

Precondition:

A precondition is a condition that must be true on entry to a member function. A class is used correctly if preconditions are never false. An operation is not responsible for doing anything sensible if its precondition fails to hold.

For example, the interface invariants of stack class say nothing about pushing yet another element on a stack that is already full. We say that isful() is a precondition of the push operation.

Post-condition:

A post-condition is a condition that must be true on exit from a member function if the precondition was valid on entry to that function. A class is implemented correctly if post-conditions are never false.

For example, after pushing an element on the stack, we know that isempty() must necessarily hold. This is a post-condition of the push operation.

19. What are the conditions that have to be met for a condition to be an invariant of the class?

Answer:

Ø The condition should hold at the end of every constructor.

Ø The condition should hold at the end of every mutator(non-const) operation.

20. What are proxy objects?

Answer:

Objects that stand for other objects are called proxy objects or surrogates.

Example:

template

class Array2D

{

public:

class Array1D

{

public:

T& operator[] (int index);

const T& operator[] (int index) const;

...

};

Array1D operator[] (int index);

const Array1D operator[] (int index) const;

...

};

The following then becomes legal:

Array2Ddata(10,20);

........

cout< // fine

Here data[3] yields an Array1D object and the operator [] invocation on that object yields the float in position(3,6) of the original two dimensional array. Clients of the Array2D class need not be aware of the presence of the Array1D class. Objects of this latter class stand for one-dimensional array objects that, conceptually, do not exist for clients of Array2D. Such clients program as if they were using real, live, two-dimensional arrays. Each Array1D object stands for a one-dimensional array that is absent from a conceptual model used by the clients of Array2D. In the above example, Array1D is a proxy class. Its instances stand for one-dimensional arrays that, conceptually, do not exist.

21. Name some pure object oriented languages.

Answer:

Ø Smalltalk,

Ø Java,

Ø Eiffel,

Ø Sather.

22. Name the operators that cannot be overloaded.

Answer:

sizeof . .* .-> :: ?:

23. What is a node class?

Answer:

A node class is a class that,

Ø relies on the base class for services and implementation,

Ø provides a wider interface to te users than its base class,

Ø relies primarily on virtual functions in its public interface

Ø depends on all its direct and indirect base class

Ø can be understood only in the context of the base class

Ø can be used as base for further derivation

Ø can be used to create objects.

A node class is a class that has added new services or functionality beyond the services inherited from its base class.

24. What is an orthogonal base class?

Answer:

If two base classes have no overlapping methods or data they are said to be independent of, or orthogonal to each other. Orthogonal in the sense means that two classes operate in different dimensions and do not interfere with each other in any way. The same derived class may inherit such classes with no difficulty.

25. What is a container class? What are the types of container classes?

Answer:

A container class is a class that is used to hold objects in memory or external storage. A container class acts as a generic holder. A container class has a predefined behavior and a well-known interface. A container class is a supporting class whose purpose is to hide the topology used for maintaining the list of objects in memory. When a container class contains a group of mixed objects, the container is called a heterogeneous container; when the container is holding a group of objects that are all the same, the container is called a homogeneous container.

26. What is a protocol class?

Answer:

An abstract class is a protocol class if:

Ø it neither contains nor inherits from classes that contain member data, non-virtual functions, or private (or protected) members of any kind.

Ø it has a non-inline virtual destructor defined with an empty implementation,

Ø all member functions other than the destructor including inherited functions, are declared pure virtual functions and left undefined.

27. What is a mixin class?

Answer:

A class that provides some but not all of the implementation for a virtual base class is often called mixin. Derivation done just for the purpose of redefining the virtual functions in the base classes is often called mixin inheritance. Mixin classes typically don't share common bases.

28. What is a concrete class?

Answer:

A concrete class is used to define a useful object that can be instantiated as an automatic variable on the program stack. The implementation of a concrete class is defined. The concrete class is not intended to be a base class and no attempt to minimize dependency on other classes in the implementation or behavior of the class.

29.What is the handle class?

Answer:

A handle is a class that maintains a pointer to an object that is programmatically accessible through the public interface of the handle class.

Explanation:

In case of abstract classes, unless one manipulates the objects of these classes through pointers and references, the benefits of the virtual functions are lost. User code may become dependent on details of implementation classes because an abstract type cannot be allocated statistically or on the stack without its size being known. Using pointers or references implies that the burden of memory management falls on the user. Another limitation of abstract class object is of fixed size. Classes however are used to represent concepts that require varying amounts of storage to implement them.

A popular technique for dealing with these issues is to separate what is used as a single object in two parts: a handle providing the user interface and a representation holding all or most of the object's state. The connection between the handle and the representation is typically a pointer in the handle. Often, handles have a bit more data than the simple representation pointer, but not much more. Hence the layout of the handle is typically stable, even when the representation changes and also that handles are small enough to move around relatively freely so that the user needn’t use the pointers and the references.

30. What is an action class?

Answer:

The simplest and most obvious way to specify an action in C++ is to write a function. However, if the action has to be delayed, has to be transmitted 'elsewhere' before being performed, requires its own data, has to be combined with other actions, etc then it often becomes attractive to provide the action in the form of a class that can execute the desired action and provide other services as well. Manipulators used with iostreams is an obvious example.

Explanation:

A common form of action class is a simple class containing just one virtual function.

class Action

{

public:

virtual int do_it( int )=0;

virtual ~Action( );

}

Given this, we can write code say a member that can store actions for later execution without using pointers to functions, without knowing anything about the objects involved, and without even knowing the name of the operation it invokes. For example:

class write_file : public Action

{

File& f;

public:

int do_it(int)

{

return fwrite( ).suceed( );

}

};

class error_message: public Action

{

response_box db(message.cstr( ),"Continue","Cancel","Retry");

switch (db.getresponse( ))

{

case 0: return 0;

case 1: abort();

case 2: current_operation.redo( );return 1;

}

};

A user of the Action class will be completely isolated from any knowledge of derived classes such as write_file and error_message.

31. When can you tell that a memory leak will occur?

Answer:

A memory leak occurs when a program loses the ability to free a block of dynamically allocated memory.

32.What is a parameterized type?

Answer:

A template is a parameterized construct or type containing generic code that can use or manipulate any type. It is called parameterized because an actual type is a parameter of the code body. Polymorphism may be achieved through parameterized types. This type of polymorphism is called parameteric polymorphism. Parameteric polymorphism is the mechanism by which the same code is used on different types passed as parameters.

33. Differentiate between a deep copy and a shallow copy?

Answer:

Deep copy involves using the contents of one object to create another instance of the same class. In a deep copy, the two objects may contain ht same information but the target object will have its own buffers and resources. the destruction of either object will not affect the remaining object. The overloaded assignment operator would create a deep copy of objects.

Shallow copy involves copying the contents of one object into another instance of the same class thus creating a mirror image. Owing to straight copying of references and pointers, the two objects will share the same externally contained contents of the other object to be unpredictable.

Explanation:

Using a copy constructor we simply copy the data values member by member. This method of copying is called shallow copy. If the object is a simple class, comprised of built in types and no pointers this would be acceptable. This function would use the values and the objects and its behavior would not be altered with a shallow copy, only the addresses of pointers that are members are copied and not the value the address is pointing to. The data values of the object would then be inadvertently altered by the function. When the function goes out of scope, the copy of the object with all its data is popped off the stack.

If the object has any pointers a deep copy needs to be executed. With the deep copy of an object, memory is allocated for the object in free store and the elements pointed to are copied. A deep copy is used for objects that are returned from a function.

34. What is an opaque pointer?

Answer:

A pointer is said to be opaque if the definition of the type to which it points to is not included in the current translation unit. A translation unit is the result of merging an implementation file with all its headers and header files.

35. What is a smart pointer?

Answer:

A smart pointer is an object that acts, looks and feels like a normal pointer but offers more functionality. In C++, smart pointers are implemented as template classes that encapsulate a pointer and override standard pointer operators. They have a number of advantages over regular pointers. They are guaranteed to be initialized as either null pointers or pointers to a heap object. Indirection through a null pointer is checked. No delete is ever necessary. Objects are automatically freed when the last pointer to them has gone away. One significant problem with these smart pointers is that unlike regular pointers, they don't respect inheritance. Smart pointers are unattractive for polymorphic code. Given below is an example for the implementation of smart pointers.

Example:

template

class smart_pointer

{

public:

smart_pointer(); // makes a null pointer

smart_pointer(const X& x) // makes pointer to copy of x

X& operator *( );

const X& operator*( ) const;

X* operator->() const;

smart_pointer(const smart_pointer &);

const smart_pointer & operator =(const smart_pointer&);

~smart_pointer();

private:

//...

};

This class implement a smart pointer to an object of type X. The object itself is located on the heap. Here is how to use it:

smart_pointer p= employee("Harris",1333);

Like other overloaded operators, p will behave like a regular pointer,

cout<<*p;

p->raise_salary(0.5);

36. What is reflexive association?

Answer:

The 'is-a' is called a reflexive association because the reflexive association permits classes to bear the is-a association not only with their super-classes but also with themselves. It differs from a 'specializes-from' as 'specializes-from' is usually used to describe the association between a super-class and a sub-class. For example:

Printer is-a printer.

37. What is slicing?

Answer:

Slicing means that the data added by a subclass are discarded when an object of the subclass is passed or returned by value or from a function expecting a base class object.

Explanation:

Consider the following class declaration:

class base

{

...

base& operator =(const base&);

base (const base&);

}

void fun( )

{

base e=m;

e=m;

}

As base copy functions don't know anything about the derived only the base part of the derived is copied. This is commonly referred to as slicing. One reason to pass objects of classes in a hierarchy is to avoid slicing. Other reasons are to preserve polymorphic behavior and to gain efficiency.

38. What is name mangling?

Answer:

Name mangling is the process through which your c++ compilers give each function in your program a unique name. In C++, all programs have at-least a few functions with the same name. Name mangling is a concession to the fact that linker always insists on all function names being unique.

Example:

In general, member names are made unique by concatenating the name of the member with that of the class e.g. given the declaration:

class Bar

{

public:

int ival;

...

};

ival becomes something like:

// a possible member name mangling

ival__3Bar

Consider this derivation:

class Foo : public Bar

{

public:

int ival;

...

}

The internal representation of a Foo object is the concatenation of its base and derived class members.

// Pseudo C++ code

// Internal representation of Foo

class Foo

{

public:

int ival__3Bar;

int ival__3Foo;

...

};

Unambiguous access of either ival members is achieved through name mangling. Member functions, because they can be overloaded, require an extensive mangling to provide each with a unique name. Here the compiler generates the same name for the two overloaded instances(Their argument lists make their instances unique).

39. What are proxy objects?

Answer:

Objects that points to other objects are called proxy objects or surrogates. Its an object that provides the same interface as its server object but does not have any functionality. During a method invocation, it routes data to the true server object and sends back the return value to the object.

40. Differentiate between declaration and definition in C++.

Answer:

A declaration introduces a name into the program; a definition provides a unique description of an entity (e.g. type, instance, and function). Declarations can be repeated in a given scope, it introduces a name in a given scope. There must be exactly one definition of every object, function or class used in a C++ program.

A declaration is a definition unless:

Ø it declares a function without specifying its body,

Ø it contains an extern specifier and no initializer or function body,

Ø it is the declaration of a static class data member without a class definition,

Ø it is a class name definition,

Ø it is a typedef declaration.

A definition is a declaration unless:

Ø it defines a static class data member,

Ø it defines a non-inline member function.

41. What is cloning?

Answer:

An object can carry out copying in two ways i.e. it can set itself to be a copy of another object, or it can return a copy of itself. The latter process is called cloning.

42. Describe the main characteristics of static functions.

Answer:

The main characteristics of static functions include,

Ø It is without the a this pointer,

Ø It can't directly access the non-static members of its class

Ø It can't be declared const, volatile or virtual.

Ø It doesn't need to be invoked through an object of its class, although for convenience, it may.

43. Will the inline function be compiled as the inline function always? Justify.

Answer:

An inline function is a request and not a command. Hence it won't be compiled as an inline function always.

Explanation:

Inline-expansion could fail if the inline function contains loops, the address of an inline function is used, or an inline function is called in a complex expression. The rules for inlining are compiler dependent.

44. Define a way other than using the keyword inline to make a function inline.

Answer:

The function must be defined inside the class.

45. How can a '::' operator be used as unary operator?

Answer:

The scope operator can be used to refer to members of the global namespace. Because the global namespace doesn’t have a name, the notation :: member-name refers to a member of the global namespace. This can be useful for referring to members of global namespace whose names have been hidden by names declared in nested local scope. Unless we specify to the compiler in which namespace to search for a declaration, the compiler simple searches the current scope, and any scopes in which the current scope is nested, to find the declaration for the name.

46. What is placement new?

Answer:

When you want to call a constructor directly, you use the placement new. Sometimes you have some raw memory that's already been allocated, and you need to construct an object in the memory you have. Operator new's special version placement new allows you to do it.

class Widget

{

public :

Widget(int widgetsize);

...

Widget* Construct_widget_int_buffer(void *buffer,int widgetsize)

{

return new(buffer) Widget(widgetsize);

}

};

This function returns a pointer to a Widget object that's constructed within the buffer passed to the function. Such a function might be useful for applications using shared memory or memory-mapped I/O, because objects in such applications must be placed at specific addresses or in memory allocated by special routines.

OOAD

1. What do you mean by analysis and design?

Analysis:

Basically, it is the process of determining what needs to be done before how it should be done. In order to accomplish this, the developer refers the existing systems and documents. So, simply it is an art of discovery.

Design:

It is the process of adopting/choosing the one among the many, which best accomplishes the users needs. So, simply, it is compromising mechanism.

2. What are the steps involved in designing?

Before getting into the design the designer should go through the SRS prepared by the System Analyst.

The main tasks of design are Architectural Design and Detailed Design.

In Architectural Design we find what are the main modules in the problem domain.

In Detailed Design we find what should be done within each module.

3. What are the main underlying concepts of object orientation?

Objects, messages, class, inheritance and polymorphism are the main concepts of object orientation.

4. What do u meant by "SBI" of an object?

SBI stands for State, Behavior and Identity. Since every object has the above three.

Ø State:

It is just a value to the attribute of an object at a particular time.

Ø Behaviour:

It describes the actions and their reactions of that object.

Ø Identity:

An object has an identity that characterizes its own existence. The identity makes it possible to distinguish any object in an unambiguous way, and independently from its state.

5. Differentiate persistent & non-persistent objects?

Persistent refers to an object's ability to transcend time or space. A persistent object stores/saves its state in a permanent storage system with out losing the information represented by the object.

A non-persistent object is said to be transient or ephemeral. By default objects are considered as non-persistent.

6. What do you meant by active and passive objects?

Active objects are one which instigate an interaction which owns a thread and they are responsible for handling control to other objects. In simple words it can be referred as client.

Passive objects are one, which passively waits for the message to be processed. It waits for another object that requires its services. In simple words it can be referred as server.

Diagram:

client server

(Active) (Passive)

7. What is meant by software development method?

Software development method describes how to model and build software systems in a reliable and reproducible way. To put it simple, methods that are used to represent ones' thinking using graphical notations.

8. What are models and meta models?

Model:

It is a complete description of something (i.e. system).

Meta model:

It describes the model elements, syntax and semantics of the notation that allows their manipulation.

9. What do you meant by static and dynamic modeling?

Static modeling is used to specify structure of the objects that exist in the problem domain. These are expressed using class, object and USECASE diagrams.

But Dynamic modeling refers representing the object interactions during runtime. It is represented by sequence, activity, collaboration and statechart diagrams.

10. How to represent the interaction between the modeling elements?

Model element is just a notation to represent (Graphically) the entities that exist in the problem domain. e.g. for modeling element is class notation, object notation etc.

Relationships are used to represent the interaction between the modeling elements.

The following are the Relationships.

Ø Association: Its' just a semantic connection two classes.

e.g.:

Ø Aggregation: Its' the relationship between two classes which are related in the fashion that master and slave. The master takes full rights than the slave. Since the slave works under the master. It is represented as line with diamond in the master area.

ex:

car contains wheels, etc.

car

Ø Containment: This relationship is applied when the part contained with in the whole part, dies when the whole part dies.

It is represented as darked diamond at the whole part.

example:

class A{

//some code

};

class B

{

A aa; // an object of class A;

// some code for class B;

};

In the above example we see that an object of class A is instantiated with in the class B. so the object class A dies when the object class B dies.we can represnt it in diagram like this.

Ø Generalization: This relationship used when we want represents a class, which captures the common states of objects of different classes. It is represented as arrow line pointed at the class, which has captured the common states.

Ø Dependency: It is the relationship between dependent and independent classes. Any change in the independent class will affect the states of the dependent class.

DIAGRAM:

class A class B

11. Why generalization is very strong?

Even though Generalization satisfies Structural, Interface, Behaviour properties. It is mathematically very strong, as it is Antisymmetric and Transitive.

Antisymmetric: employee is a person, but not all persons are employees. Mathematically all As’ are B, but all Bs’ not A.

Transitive: A=>B, B=>c then A=>c.

A. Salesman.

B. Employee.

C. Person.

Note: All the other relationships satisfy all the properties like Structural properties, Interface properties, Behaviour properties.

12. Differentiate Aggregation and containment?

Aggregation is the relationship between the whole and a part. We can add/subtract some properties in the part (slave) side. It won't affect the whole part.

Best example is Car, which contains the wheels and some extra parts. Even though the parts are not there we can call it as car.

But, in the case of containment the whole part is affected when the part within that got affected. The human body is an apt example for this relationship. When the whole body dies the parts (heart etc) are died.

13. Can link and Association applied interchangeably?

No, You cannot apply the link and Association interchangeably. Since link is used represent the relationship between the two objects.

But Association is used represent the relationship between the two classes.

link :: student:Abhilash course:MCA

Association:: student course

14. what is meant by "method-wars"?

Before 1994 there were different methodologies like Rumbaugh, Booch, Jacobson, Meyer etc who followed their own notations to model the systems. The developers were in a dilemma to choose the method which best accomplishes their needs. This particular span was called as "method-wars"

15. Whether unified method and unified modeling language are same or different?

Unified method is convergence of the Rumbaugh and Booch.

Unified modeling lang. is the fusion of Rumbaugh, Booch and Jacobson as well as Betrand Meyer (whose contribution is "sequence diagram"). Its' the superset of all the methodologies.

16. Who were the three famous amigos and what was their contribution to the object community?

The Three amigos namely,

Ø James Rumbaugh (OMT): A veteran in analysis who came up with an idea about the objects and their Relationships (in particular Associations).

Ø Grady Booch: A veteran in design who came up with an idea about partitioning of systems into subsystems.

Ø Ivar Jacobson (Objectory): The father of USECASES, who described about the user and system interaction.

17. Differentiate the class representation of Booch, Rumbaugh and UML?

If you look at the class representaiton of Rumbaugh and UML, It is some what similar and both are very easy to draw.

Representation: OMT UML.

Diagram:

Booch: In this method classes are represented as "Clouds" which are not very easy to draw as for as the developer's view is concern.

Diagram:

18. What is an USECASE? Why it is needed?

A Use Case is a description of a set of sequence of actions that a system performs that yields an observable result of value to a particular action.

In SSAD process <=> In OOAD USECASE. It is represented elliptically.

Representation:

19. Who is an Actor?

An Actor is someone or something that must interact with the system.In addition to that an Actor initiates the process(that is USECASE).

It is represented as a stickman like this.

Diagram:




20. What is guard condition?

Guard condition is one, which acts as a firewall. The access from a particular object can be made only when the particular condition is met.

For Example,

customer check customer number ATM.

Here the object on the customer accesses the ATM facility only when the guard condition is met.

21. Differentiate the following notations?

I: :obj1 :obj2

II: :obj1 :obj2

In the above representation I, obj1 sends message to obj2. But in the case of II the data is transferred from obj1 to obj2.

22. USECASE is an implementation independent notation. How will the designer give the implementation details of a particular USECASE to the programmer?

This can be accomplished by specifying the relationship called "refinement” which talks about the two different abstraction of the same thing.

Or example,

calculate pay calculate

class1 class2 class3

23. Suppose a class acts an Actor in the problem domain, how to represent it in the static model?

In this scenario you can use “stereotype”. Since stereotype is just a string that gives extra semantic to the particular entity/model element. It is given with in the << >>.

class A

<<>>

attributes

methods.

24. Why does the function arguments are called as "signatures"?

The arguments distinguish functions with the same name (functional polymorphism). The name alone does not necessarily identify a unique function. However, the name and its arguments (signatures) will uniquely identify a function.

In real life we see suppose, in class there are two guys with same name, but they can be easily identified by their signatures. The same concept is applied here.

ex:

class person

{

public:

char getsex();

void setsex(char);

void setsex(int);

};

In the above example we see that there is a function setsex() with same name but with different signature.